GIVEN A: Total number of possible arrangements = 20! GIVEN B: P(No student will sit on the same seat) = 0.3679 [Rounded off to 4 decimal places] GIVEN C: Inclusion – Exclusion as written below....

Given the following items please answer the question below. GIVEN A: Total number of possible arrangements = 20! GIVEN B: P(No student will sit on the same seat) =1-11!+12!-13!+…-119!+120! = 0.3679 [Rounded off to 4 decimal places] GIVEN C: Inclusion – Exclusion as written below. Question: SHOW Logic and steps needed to arrive at the answer in (Given B) above with the Inclusion – Exclusion Principle stated above. The answer should show how to reduce and collapse factorials given a to the answer above shown in Given B; In other words, please show how Is used to reduce to the answer shown in Given B above. Please use the following SCENARIO when providing your answer. SCENARIO to use: A certain class has 20 students, and meets on Mondays and Wednesdays in a classroom with exactly 20 seats. In a certain week, everyone in the class attends both days. On both days, the students choose their seats completely randomly (with one student per seat). Find the probability that no one sits in the same seat on both days of that week.