From this, we obtain the following difference equation Yn Yn+1 = 1+ p- (8) .2 Yn-m where p = . From now on, we handle the difference equation (8). The unique positive equilibrium point of Eq.(8) is...


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From this, we obtain the following difference equation<br>Yn<br>Yn+1 = 1+ p-<br>(8)<br>.2<br>Yn-m<br>where p = . From now on, we handle the difference equation (8). The unique<br>positive equilibrium point of Eq.(8) is<br>%3|<br>Example 11 Consider Eq.(8) for m = 5 and p 0.7. Hence we have following<br>difference equation<br>Yn<br>Yn+1 = 1+0.7<br>(17)<br>Let the initial conditions are y-5 = 10, y-4 = 6, y-3 = 8,y-2 = 4,y-1 =<br>3 and yo = 5. Then unique positive equilibrium point of Eq.(17) is globally<br>asymptotically stable. See Figure 1.<br>2.5<br>2.0<br>1.5<br>1.0<br>100<br>200<br>300<br>400<br>500<br>600<br>Figure 1: Plot of Eq. (17).<br>

Extracted text: From this, we obtain the following difference equation Yn Yn+1 = 1+ p- (8) .2 Yn-m where p = . From now on, we handle the difference equation (8). The unique positive equilibrium point of Eq.(8) is %3| Example 11 Consider Eq.(8) for m = 5 and p 0.7. Hence we have following difference equation Yn Yn+1 = 1+0.7 (17) Let the initial conditions are y-5 = 10, y-4 = 6, y-3 = 8,y-2 = 4,y-1 = 3 and yo = 5. Then unique positive equilibrium point of Eq.(17) is globally asymptotically stable. See Figure 1. 2.5 2.0 1.5 1.0 100 200 300 400 500 600 Figure 1: Plot of Eq. (17).

Jun 07, 2022
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