From a box containing 4 black balls and 2 green balls, 3 balls are drawn in succession, each ball being replaced in the box before the next draw is made. Find the probability distribution for the...

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From a box containing 4 black balls and 2 green balls, 3 balls are drawn in succession, each ball being replaced in the box before the next draw is made. Find the probability distribution for the number of green balls.

Answered Same DayDec 26, 2021

Answer To: From a box containing 4 black balls and 2 green balls, 3 balls are drawn in succession, each ball...

Robert answered on Dec 26 2021
124 Votes
P(green ball on any trial) = 2/(2+4) = 2/6 = 1/3 = 0.333333 because there are
2 green balls out of total 6 balls
Let X denote number of green balls in n = 3 independent draws, where each
has a probability p = 0.333333
We denote this by:
X ∼ Binomial(n = 3, p = 0.333333)
Probability of x number of green balls...
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