Formula Second Order Taylor Series Method y(x) = y(x;) + hy'(x;) + "(x,) When the Taylor's series is truncated after three terms, it is called second order Taylor's series method. Else, we write as...


By using
second order Taylor's series method formula solve the ordinary differentation equation.


Formula<br>Second Order Taylor Series Method<br>y(x) = y(x;) + hy'(x;) +

Extracted text: Formula Second Order Taylor Series Method y(x) = y(x;) + hy'(x;) + "(x,) When the Taylor's series is truncated after three terms, it is called second order Taylor's series method. Else, we write as Vis = y; + hy + 2!
5. Solve the following initial value problem (IVP)<br>y' - xy = x; v(0) = 1<br>by using<br>(c) third-order Taylor's series method with h = 0.2,0.25,0.5 and 0 sxsl.<br>Hence, if the exact solution is y = 2eT -1, find its errors.<br>ANSWER:<br>(c) h= 0.2<br>kerrot|<br>exact<br>y.<br>1.000<br>1.000<br>1<br>0.2<br>1.040<br>1.040<br>0.000<br>0.4<br>1.166<br>1.167<br>0.001<br>3.<br>0.6<br>1.393<br>1.394<br>0.001<br>4<br>0.8<br>1.752<br>1.754<br>0.002<br>5<br>1.0<br>2.293<br>2.297<br>0.004<br>h = 0.25<br>Jerrot|<br>exact<br>1.000<br>1.000<br>1<br>0.25<br>1.062<br>1.063<br>0.001<br>0.50<br>1.263<br>1.266<br>0.003<br>3<br>0.75<br>1.643<br>1.650<br>0.007<br>4<br>1.00<br>2.285<br>2.297<br>0.012<br>h = 0.5<br>kerrot|<br>exact<br>y.<br>1.000<br>1.000<br>1<br>0.5<br>1.250<br>1.266<br>0.016<br>1.0<br>2.241<br>2.297<br>0.056<br>

Extracted text: 5. Solve the following initial value problem (IVP) y' - xy = x; v(0) = 1 by using (c) third-order Taylor's series method with h = 0.2,0.25,0.5 and 0 sxsl. Hence, if the exact solution is y = 2eT -1, find its errors. ANSWER: (c) h= 0.2 kerrot| exact y. 1.000 1.000 1 0.2 1.040 1.040 0.000 0.4 1.166 1.167 0.001 3. 0.6 1.393 1.394 0.001 4 0.8 1.752 1.754 0.002 5 1.0 2.293 2.297 0.004 h = 0.25 Jerrot| exact 1.000 1.000 1 0.25 1.062 1.063 0.001 0.50 1.263 1.266 0.003 3 0.75 1.643 1.650 0.007 4 1.00 2.285 2.297 0.012 h = 0.5 kerrot| exact y. 1.000 1.000 1 0.5 1.250 1.266 0.016 1.0 2.241 2.297 0.056

Jun 04, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here