. For two factors-starchy or sugary, and green base leaf or white base leaf-the following counts for the progeny of self-fertilized heterozygotes were observed (Fisher 1958): Туре Count Starchy green...


. For two factors-starchy or sugary, and green base leaf or white base leaf-the<br>following counts for the progeny of self-fertilized heterozygotes were observed<br>(Fisher 1958):<br>Туре<br>Count<br>Starchy green<br>Starchy white<br>Sugary green<br>Sugary white<br>1997<br>906<br>904<br>32<br>According to genetic theory, the cell probabilities are .25(2 + 0), .25(1 - 0),<br>25(1 ), and .2560, where 0(0 < 0<1) is a parameter related to the linkage<br>of the factors.<br>6.<br>number of counts in the first cell is n(2 0)/4; if this expected number is<br>equated to the count X1, the following estimate is obtained:<br>consider two other estimates of 0. (1) The expected<br>4X1<br>п<br>(2) The same procedure done for the last cell yields<br>4X4<br>n<br>Compute these estimates. Using that X and X4 are binomial random variables<br>show that these estimates are unbiased, and obtain expressions for their vari-<br>ances. Evaluate the estimated standard errors and compare them to the estimated<br>standard error of the mle<br>

Extracted text: . For two factors-starchy or sugary, and green base leaf or white base leaf-the following counts for the progeny of self-fertilized heterozygotes were observed (Fisher 1958): Туре Count Starchy green Starchy white Sugary green Sugary white 1997 906 904 32 According to genetic theory, the cell probabilities are .25(2 + 0), .25(1 - 0), 25(1 ), and .2560, where 0(0 <><1) is="" a="" parameter="" related="" to="" the="" linkage="" of="" the="" factors.="" 6.="" number="" of="" counts="" in="" the="" first="" cell="" is="" n(2="" 0)/4;="" if="" this="" expected="" number="" is="" equated="" to="" the="" count="" x1,="" the="" following="" estimate="" is="" obtained:="" consider="" two="" other="" estimates="" of="" 0.="" (1)="" the="" expected="" 4x1="" п="" (2)="" the="" same="" procedure="" done="" for="" the="" last="" cell="" yields="" 4x4="" n="" compute="" these="" estimates.="" using="" that="" x="" and="" x4="" are="" binomial="" random="" variables="" show="" that="" these="" estimates="" are="" unbiased,="" and="" obtain="" expressions="" for="" their="" vari-="" ances.="" evaluate="" the="" estimated="" standard="" errors="" and="" compare="" them="" to="" the="" estimated="" standard="" error="" of="" the="">

Jun 01, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here