For some t > 1, let X be a random variable taking the values 0 and t, with probabilities
Then E[X] = 1 and Var(X) = t−1. Consider the probability P(|X − 1| > a).
a. Verify the following: if t = 10 and a = 8 then P(|X − 1| > a)=1/10 and Chebyshev’s inequality gives an upper bound for this probability of 9/64. The difference is 9/64 − 1/10 ≈ 0.04. We will say that for t = 10 the Chebyshev gap for X at a = 8 is 0.04.
b. Compute the Chebyshev gap for t = 10 at a = 5 and at a = 10.
c. Can you find a gap smaller than 0.01, smaller than 0.001, smaller than 0.0001?
d. Do you think one could improve Chebyshev’s inequality, i.e., find an upper bound closer to the true probabilities?
Already registered? Login
Not Account? Sign up
Enter your email address to reset your password
Back to Login? Click here