14:332:548, Error Control Coding Homework 2 Rutgers University 1. For any a ∈ Z∗p = {1, . . . , p − 1}, with p being a prime, define the function fa(x) : Z∗p → Z∗p such that fa(x) = a · x (mod p). (a)...

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Answered Same DayFeb 09, 2022

Answer To: 14:332:548, Error Control Coding Homework 2 Rutgers University 1. For any a ∈ Z∗p = {1, . . . , p −...

Rajeswari answered on Feb 09 2022
116 Votes
100401 assignment
Qno.1
Give that a belongs to
, where p is prime.
such that
a) To prove that fa is a bijection.
Let us assume if possible
Sin
ce p is prime this means x mod p = y mod p for x in Zp.
But since p is prime and all elements are less than p this is possible only if x =y
Or fa function is one to one.
For any number of the form a.x mod p we can find a unique number is Zp which is the pre image because p is prime and hence 1,2,3…p-1 cannot divide p. Thus inverse would be unique.
Hence the function f_a is bijective.
b) To deduce that there is multiplicative inverse.
Let us take any two elements x and y from Zp. Obviously x and y are positive integers and less than p and not dividing p.
Hence x mod p *y mod p = xy mod p and this belongs to Zp being any integer less than p.
Thus closed.
Associative since multiplication under modulo is associative by number theory.
Identity element is obviously 1 since for any element we get x*1 = 1*x = x the same element
Inverse part:
For any element in Zp* we have gcd (x,p) =1 since p is prime
Hence 1 =mx+np (By Euclidean algorithm)
Obviously p does not divide x, and hence the product mx mod p = 1
Since 1 is an identity element in Zp*, we find every element x has an inverse in Zp*
Ie. Proved that these numbers form a group under multiplication mod p.
Qno.4
a) Given that G = and
If automorphism then we must have
i.e.
The left side would equal right side if and only if a=
Only then we would have the condition...
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