For all set s A,Band C, An(B-c)C(AnB)-(Anc) Proof: het A, B and C sets. Let xE An(B-c) be any XE A and xe (B-c) by definition of intersection X E A and (aE Band x¢ c) by defntin of Set difference ....

Can you please check my prove and please let me know if I did it correctly. Thank you! One more question , is x is not in (A and B ) by definition of set different or set of intersection? Directions for the problem: use element argument to prove number 11. Assume that all sets are subset of a universal of U.For all set s A,Band C, An(B-c)C(AnB)-(Anc)<br>Proof:<br>het A, B and C<br>sets. Let xE An(B-c)<br>be<br>any<br>XE A and xe (B-c) by definition of intersection<br>X E A<br>and (aE Band x¢ c) by defntin of<br>Set difference .<br>Thus *E(A n B) biy definitioni of intersecton and<br>in additim<br>X € (A nc) by defimtion of set differen ce,<br>Theretore<br>X € (AnB) - (Anc) by definitun of<br>Set difference .<br>Hence,<br>A n (B-C) E (ANB) - (Anc) by definition<br>of sub sets.<br>

Extracted text: For all set s A,Band C, An(B-c)C(AnB)-(Anc) Proof: het A, B and C sets. Let xE An(B-c) be any XE A and xe (B-c) by definition of intersection X E A and (aE Band x¢ c) by defntin of Set difference . Thus *E(A n B) biy definitioni of intersecton and in additim X € (A nc) by defimtion of set differen ce, Theretore X € (AnB) - (Anc) by definitun of Set difference . Hence, A n (B-C) E (ANB) - (Anc) by definition of sub sets.

Jun 04, 2022
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