First = 0, Last = 82nd Iteration -> First = 5, Last = 83rd Iteration -> First = 5, Last = 61st Iteration -> First = 0, Last = 82nd Iteration -> First = 0, Last = 33rd Iteration -> First = 2, Last...


Binary Search algorithm uses the divide-and-conquer technique to find elements in O(logn) steps. Given the following sorted array that has 9 elements,<br>what is the scope of the search (First index and last index of the array segment) in each iteration of the binary search algorithm while looking for the<br>element
First = 0, Last = 8 2nd Iteration -> First = 5, Last = 8 3rd Iteration -> First = 5, Last = 6 1st Iteration -> First = 0, Last = 8 2nd Iteration -> First = 0, Last = 3 3rd Iteration -> First = 2, Last = 3 1st Iteration -> First = 0, Last = 8 2nd Iteration -> First = 5, Last = 8 3rd Iteration -> First = 7, Last = 8 4th Iteration -> First = 8, Last = 8 1st Iteration -> First = 0, Last = 8 2nd Iteration -> First = 0, Last = 3 3rd Iteration -> First = 2, Last = 3 4th Iteration -> First = 3, Last = 3 "/>
Extracted text: Binary Search algorithm uses the divide-and-conquer technique to find elements in O(logn) steps. Given the following sorted array that has 9 elements, what is the scope of the search (First index and last index of the array segment) in each iteration of the binary search algorithm while looking for the element "51"? Note: Numbers that show up in the first row are the array indexes 2 3 4 6 7 12 19 21 30 32 37 44 51 • 1st Iteration -> First = 0, Last = 8 2nd Iteration -> First = 5, Last = 8 3rd Iteration -> First = 5, Last = 6 1st Iteration -> First = 0, Last = 8 2nd Iteration -> First = 0, Last = 3 3rd Iteration -> First = 2, Last = 3 1st Iteration -> First = 0, Last = 8 2nd Iteration -> First = 5, Last = 8 3rd Iteration -> First = 7, Last = 8 4th Iteration -> First = 8, Last = 8 1st Iteration -> First = 0, Last = 8 2nd Iteration -> First = 0, Last = 3 3rd Iteration -> First = 2, Last = 3 4th Iteration -> First = 3, Last = 3

Jun 07, 2022
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