Find the standard deviation, s, of sample data summarized in the frequency distribution table below by using the formula below, where x represents the class midpoint, frepresents the class frequency,...


Find the standard deviation, s, of sample data summarized in the frequency distribution table below by using the formula below, where x represents the class<br>midpoint, frepresents the class frequency, and n represents the total number of sample values. Also, compare the computed standard deviation to the standard<br>deviation obtained from the original list of data values, 11.1.<br>S=<br>n(n - 1)<br>Interval<br>30-36<br>37-43<br>44-50<br>51-57<br>58-64<br>65-71<br>72-78<br>Frequency<br>4<br>4<br>18<br>33<br>36<br>Standard deviation =9.6 (Round to one decimal place as needed.)<br>Consider a difference of 20% between two values of a standard deviation to be significant. How does this computed value compare with the given standard<br>deviation, 11.1?<br>O A. The computed value is significantly greater than the given value.<br>O B. The computed value is significantly less than the given value.<br>C. The computed value is not significantly different from the given value.<br>

Extracted text: Find the standard deviation, s, of sample data summarized in the frequency distribution table below by using the formula below, where x represents the class midpoint, frepresents the class frequency, and n represents the total number of sample values. Also, compare the computed standard deviation to the standard deviation obtained from the original list of data values, 11.1. S= n(n - 1) Interval 30-36 37-43 44-50 51-57 58-64 65-71 72-78 Frequency 4 4 18 33 36 Standard deviation =9.6 (Round to one decimal place as needed.) Consider a difference of 20% between two values of a standard deviation to be significant. How does this computed value compare with the given standard deviation, 11.1? O A. The computed value is significantly greater than the given value. O B. The computed value is significantly less than the given value. C. The computed value is not significantly different from the given value.

Jun 01, 2022
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