Find the solution of the given initial value problem. y'. + y = f(t),y(0) = 6,y' (0) = 5 where S 1, 0


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Find the solution of the given initial value problem.<br>y'.<br>+ y = f(t),y(0) = 6,y' (0) = 5<br>where<br>S 1, 0<1<<br>0, <1< 0<br>f(t) =<br>y(t) = ug/2(1)[sint – 1] + 11sin t – cost + 1<br>y(t) = Ua/2(1)[sint – 1] – 5cost – 5sint – 1<br>O y(t) = Ua/2(t)[cost – 1] + 4cost + 6sint + 1<br>O y(t) = u„/2(t)[sint – 1] + 6cost + 5sint<br>O y(t) = Ua/2(t)[sint – 1] + 5cost + 5sint + 1<br>

Extracted text: Find the solution of the given initial value problem. y'. + y = f(t),y(0) = 6,y' (0) = 5 where S 1, 0<>< 0,=""><>< 0="" f(t)="y(t)" =="" ug/2(1)[sint="" –="" 1]="" +="" 11sin="" t="" –="" cost="" +="" 1="" y(t)="Ua/2(1)[sint" –="" 1]="" –="" 5cost="" –="" 5sint="" –="" 1="" o="" y(t)="Ua/2(t)[cost" –="" 1]="" +="" 4cost="" +="" 6sint="" +="" 1="" o="" y(t)="u„/2(t)[sint" –="" 1]="" +="" 6cost="" +="" 5sint="" o="" y(t)="Ua/2(t)[sint" –="" 1]="" +="" 5cost="" +="" 5sint="" +="">

Jun 05, 2022
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