Find an equation for the tangent to the curve at the given point. 1) h(x) = t3 - 25t - 1, (5, XXXXXXXXXXA) y = -1 B) y = 50t - 251 C) y = 50t - 1 D) y = 49t - 251 Graph the equation and its tangent....

Calculus 1-Test 2 Summer 2012 Name___________________________________ MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Find an equation for the tangent to the curve at the given point. 3 1) h(x)= t - 25t- 1, (5,-1) 1) A) y=-1 B) y= 50t- 251 C) y= 50t- 1 D) y= 49t- 251 Graph the equation and its tangent. 3 2) Graph y= x - 2 and the tangent to the curve at the point whose x-coordinate is 0. 2) A) B) C) D) 1Find the slope of the curve at the indicated point. 6 3) y= , x= 5 3) 9+ x 3 3 3 3 m= m=- m=- m= A) B) C) D) 7 7 98 98 Solve the problem. 1 4) Find equations of all tangents to the curve f(x)= that have slope-1. 4) x 36 + A) y=-x+ 38, y=-x- 34 B) y=-x- 34 C) y=-x- 34, y=-x- 38 D) y=-x+ 38 Calculate the derivative of the function. Then find the value of the derivative as specified. 8 f(x)= ; f (-1) 5) 5) x 8 2 A) f (x)=- 8x ; f (-1) =- 8 B) f (x)=- ; f (-1) =-8 2 x 8 C) f (x)= 8; f (-1)= 8 D) f (x)= ; f (-1)= 8 2 x 8 6) f(x)= ; f (0) 6) x 2 + 8 2 A) f (x)= ; f (0)= 2 B) f (x)=- 8(x+ 2) ; f (0)=- 32 2 (x+ 2) 8 C) f (x)=- ; f (0)=-2 D) f (x)= 8; f (0)= 8 2 (x+ 2) Find the indicated derivative. dv 5 7) if v = t+ 7) dt t 5 5 5 5 A) t- B) 1- C) 1+ D) 1- 2 t 2 2 t t t Find the derivative. 4 3 8) y= 2x - 8x + 9 8) 3 2 3 2 3 2 3 2 A) 8x - 24x - 7 B) 4x + 3x C) 8x - 24x D) 4x + 3x - 7 Find the second derivative. 3 13x 9) y= - 7 9) 6 13 13 2 A) x B) 13x- 7 C) x D) 13x 2 6 2Find y . 1 1 2 10) y= + 5 x - + 5 10) 2 2 x x 4 1 4 4 A) + 10x B) - + 10x C) + 10x D) - - 10x 5 5 3 5 x x x x Find the derivative of the function. 2 x - 3x+ 2 11) y= 11) 7 x - 2 8 7 6 8 7 6 -5x + 19x - 14x - 4x+ 6 -5x + 18x - 13x - 4x+ 6 A) y = B) y = 7 2 7 2 (x - 2) (x - 2) 8 7 6 8 7 6 -5x + 18x - 14x - 4x+ 6 -5x + 18x - 14x - 3x+ 6 C) y = D) y = 7 2 7 2 (x - 2) (x - 2) -1 3 12) f(t) = (2- t)(2+ t ) 12) 3 2 3 2 - 2t + 6t - 2 - 4t + 6t - 2 A) f (t)= B) f (t)= 2 2 3 3 (2+ t ) (2+ t ) 3 2 3 2 2t - 6t - 2 - - 2t 6t 2 C) f (t)= D) f (t)= 2 3 3 2+ t...