4/16/2018 Mat 175 Professor Gebuza Final Exam Study Guide Chapter 1, sections XXXXXXXXXX  Graphs and solutions of equations and functions: o x and y intercepts, domain and range  Distance and...

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Final Exam monitored on camera, via Webex.Subject: College Algebra & Trigonometry
Unit: MAT 175Time length: Two hours.Number of questions: Not specified. All previous exams consisted of 11 questions, so, maybe it will be 11 again? Unsure.
Deadline: Tuesday, 11 May at 6pm/1800. Exam must be opened at 6pm/1800, and completed by 8pm/2000.Requesting Himanshu take this exam, if they are available.


4/16/2018 Mat 175 Professor Gebuza Final Exam Study Guide Chapter 1, sections 1.1-1.6  Graphs and solutions of equations and functions: o x and y intercepts, domain and range  Distance and midpoint between two points o Equation of a circle: center and radius  Linear functions: o Slope, zeros o Slope-intercept and point-slope equation o Vertical, horizontal, parallel and perpendicular lines o Applications of slope: Average Rate of Change  Solving equations and inequalities in one variable Chapter 2, sections 2.1-2.6  Increasing, decreasing and constant functions  Relative maxima and minima  Piecewise functions  Composition of functions  Symmetry with respect to x, y-axis and origin (even and odd functions)  Transformations of graphs: o Vertical and horizontal translations of graphs o Reflections across x-axis and y-axis o Vertical and horizontal stretching and shrinking  Direct and indirect variation: variation constant and equation of variation Chapter 3, sections 3.1-3.5  Complex numbers in a + bi form  Addition, subtraction and multiplication of complex numbers  Solving quadratic equations: o Principle of Zero products and Square Roots o Completing the Square and Quadratic Formula o Discriminant of the quadratic equation 4/16/2018 Mat 175 Professor Gebuza Final Exam Study Guide  Graphing quadratic functions: o Vertex, axis of symmetry, minimum and maximum values, domain and range, intervals on which quadratic function increases/decreases  Solving rational and radical equations  Solving equations and inequalities with absolute value Chapter 4, section 4.1 & 4.2  Polynomial functions: leading term, leading coefficient & degree of function  Leading term test  Zeros of polynomial functions, Multiplicity and Intermediate Value theorem  Graphing polynomial functions Chapter 9, section 9.1  Solving system of equations graphically, using the substitution or elimination method Chapter 6, sections 6.1-6.6  Trigonometric functions of acute angles in right triangle: o Reciprocal functions o Trigonometric functions of 45, 30 & 60 degree angles o Cofunction identities  Angle measure in DMS form  Solving a right triangle: o Application problems: angle of elevation, angle of depression, bearing  Trigonometric functions of any angle: o Positive and negative rotation, coterminal angles, complimentary and supplementary angles, reference angle  Unit circle: o Angle measure in radians o Converting between degree and radian (radian & degree) measures o Angular and linear speeds 4/16/2018 Mat 175 Professor Gebuza Final Exam Study Guide  Trigonometric functions using a unit circle: o Reflections on a unit circle  Graphs of trigonometric functions: o Domain and range, period, amplitude o Odd and even trigonometric functions  Transformations of Sine and Cosine functions: o Vertical and horizontal shift o Vertical and horizontal stretching or shrinking o Reflections across x and y-axis o Combined transformations Note: Anything covered in class, in Blackboard, in the homework, or in the textbook is eligible for the exam. However, the above topics represent the major part of the exam.
Answered 2 days AfterMay 09, 2021

Answer To: 4/16/2018 Mat 175 Professor Gebuza Final Exam Study Guide Chapter 1, sections XXXXXXXXXX  Graphs...

Rajeswari answered on May 11 2021
150 Votes
83622 assignment
Substitute (1,-4) in the equation
Left side = 2(1)-(-4) = 6 equals right side
He
nce true.
Keep y on one side and others on next side
2x-y = 6
-y = -2x+6
Y = 2x-6 is the slope intercept form.
Slope = 2
Graph is not seen in your picture
Y intercept = -6
Put y =0 to get x intercept as
X =3
Hence line passes through (3,0) and (0,-6)
Select that graph
Qno.4
Any line parallel to y = 2x-6 would be of the form
Y = 2x+k for some k.
Since it passes through (2,6) substitute y =6 and x =2 to find...
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