PowerPoint Presentation MGMT90141 Business Analysis and Decision Making Week 1 – Introduction to Business Analytics and Linear Programming Dr Lusheng Shao Senior Lecturer of Operations Management...

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Answered Same DayNov 14, 2021

Answer To: PowerPoint Presentation MGMT90141 Business Analysis and Decision Making Week 1 – Introduction to...

Himanshu answered on Nov 17 2021
142 Votes
Ans 1 a.
Let x1 be Newsprint
x2 be the Packaging
x3 be the high-quality photographic print
sources,
a1 be the Newspaper
b1 be the White office paper
c1 be the Cardboard 
tons = p1
capacity = q1
x1 = 500
x2 = 600
x3 = 300
a1 = 0.85p1* (x1)
a1 = 0.8p1*(x2)
a1 = 0p1*(x3)
b1 = 0.9p1*(x1)
b1 = 0.85p1*(x2)
b1 = 0.8p1*(x3)
c1 = 0.8p1*(x1)
c1 = 0.7p1*(x2)
c1 = 0p1*(x3)
a1*x1 = 6.5, a1*x2 = 11, a1*x3=0
b1*x1 = 4.7, b1*x2 = 7.75, b1*x3 = 8.5
c1*x1= 7.5, c1*x2 = 8.5, c1*x3 = 0
p1= 15a1, 19b1, 17c1
q1 = 600a1, 800b1, 600c1
Minimize value or z = 500x1 + 600x2 + 300x3
b. b1 = 0.9p1*(x1)
= 0.9(19) * 4.75
= 81.225
c.
a1 = 0.8p1*x2
11≤ 0.8 * 15*
≤ 0.91667
    
d. B1 = 800
e. (-600 +480+ 420) / 16*17
= -1.10
f. no optimal will not change
g.
f. 500x1+700x2+300x3
= 500*15 +700*19+300*17
= 7500 + 13300 + 5100
= 25900
Cost will increase to 1900 (100*19)
I. Ans 2. p1 = engineers
Q1 = technicians
F1 = hardware cost
L1 = profit
X1≤300, x2≤400, x1+x2 ≥ $1m
We define four binary variables xA, xB, xC, xD as follows: xA := 1 if Project A is selected 0 otherwise,
xB := 1 if Project B is selected, 0 otherwise.
xC := 1 if Project C is selected 0 otherwise,
xD := 1 if Project D is selected, 0 otherwise.
1.A ≤ c or equivalently A − B ≤ 0
2. B ≤c or equivalently B − e ≤ 0
3. xD + xf = 1
4. a+b+c+d+e+f ≤5
    
II. X = two-night package, y = Friday night only, z = Saturday night only
Conference attendee = p, regular customer = q
For reservations
X1 = two-night package, y1 = Friday night only, z1 = Saturday night only
Conference attendee = p1, regular customer = q1
X+p = 200, y+p = 120, z+p = 130
X+q = 300, y+q= 150, z+q = 160
X1+p1 = 50, y1+p1 = 30, z1+p1 = 20
X1+q1= 30, y1+q1 =40, z1+q1 = 30
Available rooms = x+p+x1+p1...
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