Evaluate Integrate Integrate

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Evaluate 0p41+tan2x dx Integrate 2sinxcosxdx Integrate cosh2x dx

005_eq2t9pk-0u0fqivf.docx

Answered Same DayDec 23, 2021

Answer To: Evaluate Integrate Integrate

Robert answered on Dec 23 2021

120 Votes

Evaluate
√(1 + tan2x) = √sec2x = sec x
0∫π/4 sec x = ln |sec x + tan x|0π/4 = ln (√2 + 1)
Integrate
Let sin x = p
=> cos x dx = dp
I = ∫2pdp =2p/ln 2 + k = 2sin x/ln 2 + k
Integrate
Let 2x = p
· 2dx = dp
· dx = dp/2
I = ∫cosh p dp/2 = 0.5sinh p =0.5sinh 2x + k

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Evaluate Integrate Integrate

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