Expand the function below as a Taylor series about a = 0. Expand to second order. This means that your series might (or might not) have a term independent of a, might (or might not) have a term linear...


Expand the function below as a Taylor series about a = 0. Expand to second order. This means<br>that your series might (or might not) have a term independent of a, might (or might not) have a<br>term linear in a (or might not), and might (or might not) have a term proportional to a?, but it<br>definitely won't have any terms involving a³, a², etc.<br>eik Va²+(y+a/2)²<br>eik/x²+(y-a/2)²<br>U (x, y)<br>2² + (y +a/2)²<br>x² + (y – a/2)²<br>Assume that r² + y² > ay and x2 + y? > a?.<br>Hint: Is this an even or odd function of a?<br>

Extracted text: Expand the function below as a Taylor series about a = 0. Expand to second order. This means that your series might (or might not) have a term independent of a, might (or might not) have a term linear in a (or might not), and might (or might not) have a term proportional to a?, but it definitely won't have any terms involving a³, a², etc. eik Va²+(y+a/2)² eik/x²+(y-a/2)² U (x, y) 2² + (y +a/2)² x² + (y – a/2)² Assume that r² + y² > ay and x2 + y? > a?. Hint: Is this an even or odd function of a?

Jun 04, 2022
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