Exercise: Table below shows the pedestrian death in accidents if the intoxication being involved ped intoxicated ped notintoxicated driver intoxicated 59 79 driver notintoxicated 266 581 (a) If one of...


I am pretty sure that b is 404/925 or 43.67% and I know I can just do 1-0.4367 technically to get the opposite probability but I want to calculate it by hand. When I do I get 926/925 though. How do I do a properly?


Exercise: Table below shows the pedestrian death in accidents if<br>the intoxication being involved<br>ped intoxicated ped notintoxicated<br>driver intoxicated<br>59<br>79<br>driver notintoxicated<br>266<br>581<br>(a) If one of the pedestrian death was randomly selected, find the<br>probability that the pedestrian was not intoxicated or the driver<br>was not intoxicated.<br>(b) If one of the pedestrian death was randomly selected, find the<br>probability that the pedestrian was intoxicated or the driver was<br>intoxicated.<br>

Extracted text: Exercise: Table below shows the pedestrian death in accidents if the intoxication being involved ped intoxicated ped notintoxicated driver intoxicated 59 79 driver notintoxicated 266 581 (a) If one of the pedestrian death was randomly selected, find the probability that the pedestrian was not intoxicated or the driver was not intoxicated. (b) If one of the pedestrian death was randomly selected, find the probability that the pedestrian was intoxicated or the driver was intoxicated.

Jun 07, 2022
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