Exercise 5 Write a method to convert an upper-case letter to a lower-case letter. (Hint: Check first to be sure that it is not lower case already.)


please i need the answers ASAP


Exercise 5<br>Write a method to convert an upper-case letter to a lower-case letter. (Hint: Check first to be<br>sure that it is not lower case already.)<br>

Extracted text: Exercise 5 Write a method to convert an upper-case letter to a lower-case letter. (Hint: Check first to be sure that it is not lower case already.)
Exercise 1<br>Create a method that takes a value and indicate whether it is positive or negative by a return a<br>Boolean value.<br>Declared as: boolean isPositive (float a)<br>Exercise 2<br>Create a method that takes a value and tell whether it is null or not.<br>Declared as: boolean isZero (float a)<br>Exercise 3<br>Create a method delta() that takes three values, a, b and e, which are the coefficients of a<br>quadratic equation and returns the value of the delta, which is given by b ² - 4ac<br>Exercise 4<br>Using the 3 methods above, create an application that calculates the roots of an equation of<br>second degree:<br>ах * + bx +с %3D0<br>For it exists, the coefficient a must be nonzero.<br>If delta is positive, then there are two distinct roots:<br>-6+ VA<br>-6 - VĀ<br>and<br>2а<br>2а<br>If delta is zero, then there is exactly one real root:<br>2a'<br>If delta is negative, there is no real solution.<br>

Extracted text: Exercise 1 Create a method that takes a value and indicate whether it is positive or negative by a return a Boolean value. Declared as: boolean isPositive (float a) Exercise 2 Create a method that takes a value and tell whether it is null or not. Declared as: boolean isZero (float a) Exercise 3 Create a method delta() that takes three values, a, b and e, which are the coefficients of a quadratic equation and returns the value of the delta, which is given by b ² - 4ac Exercise 4 Using the 3 methods above, create an application that calculates the roots of an equation of second degree: ах * + bx +с %3D0 For it exists, the coefficient a must be nonzero. If delta is positive, then there are two distinct roots: -6+ VA -6 - VĀ and 2а 2а If delta is zero, then there is exactly one real root: 2a' If delta is negative, there is no real solution.

Jun 06, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here