Exercise 1 Consider the differential equation: y(6)–16y" = 3–2e"+6x sin 2r (Ej). By using the method of undetermined coefficients, the solution of the asso- ciated homogeneous equation of (E)) is a....

Extracted text: Exercise 1 Consider the differential equation: y(6)–16y" = 3–2e"+6x sin 2r (Ej). By using the method of undetermined coefficients, the solution of the asso- ciated homogeneous equation of (E)) is a. Ye = C1 + Czx + Cze²" + C4e¬2# + C3 cos 2r + Cg sin 2r b. ye = C1 + C2r + Cze²" + C4xe²* + C3 cos 2r + C6 sin 2r c. ye = C1 + Czx + C3e" + C4e- + C5e** + Ce¬4z d. ye = C1 + C2r + Cze2* + C4e-2= + C5 cos 4r + Có sin 4r -2x %3D %3D %3D