Example.19-31. By consjdering the limit of three points, Lagrange's interpolation formula for arguments x9, xo + E , and x1 as e → 0, obtain the formula : (x1 – x) (x + x1 – 2xo) (x1 – x0)2 (x-x0) (x...

Example.19-31. By consjdering the limit of three points, Lagrange's interpolation<br>formula for arguments x9, xo + E , and x1 as e → 0, obtain the formula :<br>(x1 – x) (x + x1 – 2xo)<br>(x1 – x0)2<br>(x-x0) (x – x1),<br>f(xo) +<br>(x – xo)²<br>P(x0) +<br>(x; – xg)2.<br>flx)<br>Ax).<br>%3D<br>Xo – X1<br>|<br>

Extracted text: Example.19-31. By consjdering the limit of three points, Lagrange's interpolation formula for arguments x9, xo + E , and x1 as e → 0, obtain the formula : (x1 – x) (x + x1 – 2xo) (x1 – x0)2 (x-x0) (x – x1), f(xo) + (x – xo)² P(x0) + (x; – xg)2. flx) Ax). %3D Xo – X1 |

Jun 03, 2022

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Example.19-31. By consjdering the limit of three points, Lagrange's interpolation formula for arguments x9, xo + E , and x1 as e → 0, obtain the formula : (x1 – x) (x + x1 – 2xo) (x1 – x0)2 (x-x0) (x...

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