Example: Find the length of the cardioid r = 1 + sin 0, 0 02T. Fund length from and multi ply yfwo 2 Cr -Tr I+2sin+siiptca - 2+ 2sne L = de T(2 2+2sine dD 2 T(2 lenth I+S\n s 2L 2( 8 S2+25in2-2...

For this problem why did we integrated from -90degre to 90degree, instead of integrating from 90degree to 270 degree? Is not the half of the cadroid fall into first and fourth quadrant?

Extracted text: Example: Find the length of the cardioid r = 1 + sin 0, 0 02T. Fund length from and multi ply yfwo 2 Cr -Tr I+2sin+siiptca - 2+ 2sne L = de T(2 2+2sine dD 2 T(2 lenth I+S\n s 2L 2( 8 S2+25in2-2 N2-2sinD de 2-25in J4-4Sin S 2- 2sin& dt let 72 h= 2-2sinD du -2Co9d 2 Cos8 de 2-25inD -212-2sin 2 v S-du 4 11 FIN