EXAMPLE 8.5 Determine current I, for the network in Fig. 8.9. Solution: Although it may appear that the network cannot be solved us- ing methods introduced thus far, one source conversion, as shown in...

EXAMPLE 8.5 Determine current I, for the network in Fig. 8.9. Solution: Although it may appear that the network cannot be solved us- ing methods introduced thus far, one source conversion, as shown in Fig. 8.10, resuls in a simple series circuit, It does not make sense to convert the voltage source to a current source because you would lose the current I in the redrawn network. Note the polarity for the equivalent voltage source as determined by the current source. ‘For the source conversion:


Extracted text: EXAMPLE 8.5 Determine current I; for the network in Fig. 8.9. Solution: Although it may appear that the network cannot be solved us- ing methods introduced thus far, one source conversion, as shown in Fig. 8.10, results in a simple series circuit. It does not make sense to convert the voltage source to a current source because you would lose the current I, in the redrawn network. Note the polarity for the equivalent voltage source as determined by the current source. For the source conversion: 4 A R1 R2