Example 5 A closed tank shown in the given figure, is given an acceleration of 3.6 m/s, the acceleration vector being inclined at an angle of 35° to the horizontal. Calculate the pressure at point M,...


Example 5<br>A closed tank shown in the given figure, is given an acceleration of 3.6 m/s, the acceleration vector<br>being inclined at an angle of 35° to the horizontal. Calculate the pressure at point M, N and R.<br>R<br>a = 3.6 m/s<br>0.5 m<br>2.0 m<br>Oil<br>(S.G. = 0.9)<br>35°<br>width = 2 m<br>10 m<br>

Extracted text: Example 5 A closed tank shown in the given figure, is given an acceleration of 3.6 m/s, the acceleration vector being inclined at an angle of 35° to the horizontal. Calculate the pressure at point M, N and R. R a = 3.6 m/s 0.5 m 2.0 m Oil (S.G. = 0.9) 35° width = 2 m 10 m

Jun 11, 2022
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