Examine the scatterplot for the data in the table below. 2 4. 3. 11 12 37 14 16 15 21 16 26 18 28 19 32 20 34 40+ 35 30 25 20- 15 10- -5 -5+ 10 15 20 5 There seems to be an outlier. Enter as a point:...


Examine the scatterplot for the data in the table below.<br>2<br>4.<br>3.<br>11<br>12<br>37<br>14<br>16<br>15<br>21<br>16<br>26<br>18<br>28<br>19<br>32<br>20<br>34<br>40+<br>35<br>30<br>25<br>20-<br>15<br>10-<br>-5<br>-5+<br>10<br>15<br>20<br>5<br>There seems to be an outlier. Enter as a point:<br>а. (х, у) %3D<br>To determine if this is truly an outlier, we first need to find the standard error of the estimate, Se.<br>Find the regression equation, round the slope and y-intercept to 2 decimals, and then use that equation to<br>find the standard error. Round this answer to one decimal.<br>b. Se =<br>What y-value is the cutoff beyond which the point (12,37) would be considered an outlier?<br>c. The cutoff is y =<br>

Extracted text: Examine the scatterplot for the data in the table below. 2 4. 3. 11 12 37 14 16 15 21 16 26 18 28 19 32 20 34 40+ 35 30 25 20- 15 10- -5 -5+ 10 15 20 5 There seems to be an outlier. Enter as a point: а. (х, у) %3D To determine if this is truly an outlier, we first need to find the standard error of the estimate, Se. Find the regression equation, round the slope and y-intercept to 2 decimals, and then use that equation to find the standard error. Round this answer to one decimal. b. Se = What y-value is the cutoff beyond which the point (12,37) would be considered an outlier? c. The cutoff is y =

Jun 02, 2022
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