Name: Score: /100 Name: Question #1 (30 points) Genotype Observed Expected Chi-square AA 210 205.71 AC 60 1.0714 CC 10 Total 280 280 Test for Hardy-Weinberg proportions by filling in the five missing...

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Answer To: Name: Score: /100 Name: Question #1 (30 points) Genotype Observed Expected Chi-square AA 210 205.71...

Rajeswari answered on Apr 29 2021
150 Votes
82373 assignment
Question #1 (30 points)
    Genotype
    Observed
    Expected
    Chi-square
    AA
    210
    205.71
    0.089466
    AC
    60
    52.5/68.571
    1.0714
    CC
    10
    21.79/5.719
    6.3793/3.2046
    Total
    280
    280
    7.5402/4.3655
Test for Hardy-Weinberg proportions by filling in the five missing values in the above table (10 points).
Chi square is calculated as (observed-expected)/expected ^2
Using this we fill up .
AA = (210-205.71)^2/205.71 = 0.089466
For AC, (60-x)^2/x = 1.0714
i.e 3600-120x+x^2...
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