Ethylene Glycol (B) 0.9 0.1 0.8 0.2 0.7 0.3 0.6 0.4 boundary Plait Point Miscibility 0.5 0.5 0.4 0.6 0.3 Tie line 0.7 0.2 0.8 0.1 0.9 Furfural (C) D 0.9 0.6 0.8 0.7 0.5 0.3 Water 0.4 0.2 0.1 G (A)...


Determine the mass fraction composition at points P, E, and R.


Ethylene Glycol<br>(B)<br>0.9<br>0.1<br>0.8<br>0.2<br>0.7<br>0.3<br>0.6<br>0.4<br>boundary<br>Plait<br>Point<br>Miscibility<br>0.5<br>0.5<br>0.4<br>0.6<br>0.3<br>Tie line<br>0.7<br>0.2<br>0.8<br>0.1<br>0.9<br>Furfural<br>(C)<br>D 0.9<br>0.6<br>0.8<br>0.7<br>0.5<br>0.3<br>Water<br>0.4<br>0.2<br>0.1 G<br>(A)<br>Mass fraction furfural<br>The ternary diagram above shows the liquid-liquid phase equilibrium for water (A) -<br>ethylene glycol (2) – furfural (C) system at 25 °C and 1 atm. The solute is ethylene<br>glycol, and furfural is the solvent that removes ethylene glycol from a binary mixture<br>with water. The furfural-rich phase is called the extract while the water-rich phase is<br>called the raffinate.<br>Mass fraction water<br>Raffinate<br>P.<br>Mass fraction ethylene glycol<br>Extract<br>E,<br>

Extracted text: Ethylene Glycol (B) 0.9 0.1 0.8 0.2 0.7 0.3 0.6 0.4 boundary Plait Point Miscibility 0.5 0.5 0.4 0.6 0.3 Tie line 0.7 0.2 0.8 0.1 0.9 Furfural (C) D 0.9 0.6 0.8 0.7 0.5 0.3 Water 0.4 0.2 0.1 G (A) Mass fraction furfural The ternary diagram above shows the liquid-liquid phase equilibrium for water (A) - ethylene glycol (2) – furfural (C) system at 25 °C and 1 atm. The solute is ethylene glycol, and furfural is the solvent that removes ethylene glycol from a binary mixture with water. The furfural-rich phase is called the extract while the water-rich phase is called the raffinate. Mass fraction water Raffinate P. Mass fraction ethylene glycol Extract E,

Jun 11, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here