Reaction conditions are 400 K and 2 bar. For the same feed, but for P = 1 bar, would the equilibrium mole fraction of ethanol be higheror lower? Ethanol is produced from ethylene via the gas-phase...

Reaction conditions are 400 K and 2 bar.

For the same feed, but for P = 1 bar, would the equilibrium mole fraction of ethanol be higher
or lower?

Extracted text: Ethanol is produced from ethylene via the gas-phase reaction C,H4(g) + H20 (g) → C2H50H (g)

Jun 10, 2022

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