ENGG*3070 – Assignment No. 3 (Due Nov 10, 2021, 11:59 Dropbox) Multiple Stations 1. A six-station dial indexing machine is designed to perform four assembly operations at stations 2 through 5 after a...

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Answered 1 days AfterNov 07, 2021

Answer To: ENGG*3070 – Assignment No. 3 (Due Nov 10, 2021, 11:59 Dropbox) Multiple Stations 1. A six-station...

Karthi answered on Nov 09 2021
127 Votes
(1)
Td = 2 min, Tc = 7+2 = 9 sec = 0.15 min Cycle rate Rc = 1/0.15 = 6.67 cycles/min
(a) Σ (mq) =
1(0.01) + 0.6(0.005) + 1(0.02) + 0.7(0.01) = 0.04
Tp = 0.15 + 0.04(2) = 0.23 min
Rp = 60/0.23 = 260.9 asbys/hr
(b) Pap = (1-0.01+1x0.01)(1-0.005+0.6x0.005)(1-0.02+1x0.02)(1-0.01+0.7x0.01)
= (1)(0.998)(1)(0.997) = 0.995
Pqp= 1 - 0.995 = 0.005
Rap = 260.9(0.995) = 259.6 good asbys/hr
(c) Station 2: fθ = 32(.25) = 8 components/min
Station 3: fθ = 20(.50) = 10 components/min
Station 4: fθ = 20(.25) = 5 components/min
Station 5: fθ = 15(1.0) = 15 components/min
The problem is that the feeder for station 4 is slower than the machine's cycle rate of 6.667
cycles/min
(d) If the machine operates at the cycle rate that is consistent with the feed rate of Station 4, then Tc
= 12 sec =
0.20 min
Tp = 0.20 + 0.04(2) = 0.28 min
Rp = 60/0.28 = 214.3 asbys/hr
Rap =...
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