Electronics Circuit: BJT biasing A Voltage Divider bias NPN BJT (Beta = 80) circuit is connected to a 16VDC supply with the following components R1= 62 KOhms, R2= 9.1 KOhms, Rc= 3.9 KOhms, and Re=...


Electronics Circuit: BJT biasing<br>A Voltage Divider bias NPN BJT (Beta = 80) circuit is<br>connected to a 16VDC supply with the following<br>components R1= 62 KOhms, R2= 9.1 KOhms, Rc= 3.9<br>KOhms, and Re= 0.68 KOhms. Determine the Base<br>Voltage (Vb).<br>а.<br>1.86 Volts<br>b.<br>1.16 Volts<br>с.<br>9.33 Volts<br>d.<br>8.17 Volts<br>

Extracted text: Electronics Circuit: BJT biasing A Voltage Divider bias NPN BJT (Beta = 80) circuit is connected to a 16VDC supply with the following components R1= 62 KOhms, R2= 9.1 KOhms, Rc= 3.9 KOhms, and Re= 0.68 KOhms. Determine the Base Voltage (Vb). а. 1.86 Volts b. 1.16 Volts с. 9.33 Volts d. 8.17 Volts

Jun 11, 2022
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