e/1FAlpQLSd5fGvqf7DZvuZAo90CldfzqtwzKegyu1JrG6-3RqG4RtgX8Q/formResponse Consider the regular subdivision of the interval [a, b] as a = x0

e/1FAlpQLSd5fGvqf7DZvuZAo90CldfzqtwzKegyu1JrG6-3RqG4RtgX8Q/formResponse<br>Consider the regular subdivision of the interval [a, b] as a = x0 < x1 < x2 < x3 < x4 =<br>b, with the step size h = x+1-xt, and define the function f on [a, b] such that f (a)<br>f(b) = 1,f(x1)<br>%3D<br>1.5, f(x2) = f (x3) = 2. Suppose that the length of the interval [a, b] is<br>%3D<br>2, then the approximation of I = f f(x)dx using composite Simpson's rule with n= 4 is:<br>О 5/2<br>5/3<br>O 10/3<br>

Extracted text: e/1FAlpQLSd5fGvqf7DZvuZAo90CldfzqtwzKegyu1JrG6-3RqG4RtgX8Q/formResponse Consider the regular subdivision of the interval [a, b] as a = x0 < x1="">< x2="">< x3="">< x4="b," with="" the="" step="" size="" h="x+1-xt," and="" define="" the="" function="" f="" on="" [a,="" b]="" such="" that="" f="" (a)="" f(b)="1,f(x1)" %3d="" 1.5,="" f(x2)="f" (x3)="2." suppose="" that="" the="" length="" of="" the="" interval="" [a,="" b]="" is="" %3d="" 2,="" then="" the="" approximation="" of="" i="f" f(x)dx="" using="" composite="" simpson's="" rule="" with="" n="4" is:="" о="" 5/2="" 5/3="" o="">

Jun 04, 2022

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e/1FAlpQLSd5fGvqf7DZvuZAo90CldfzqtwzKegyu1JrG6-3RqG4RtgX8Q/formResponse Consider the regular subdivision of the interval [a, b] as a = x0

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