Can you help me solve this? The first part of the question got cutoff but it states, for any integer n greater than or equal to 1, prove that: (e) 1 +33 +5 + +(2n – 1) = n²(2n² – 1). [Hint: Separate...

Can you help me solve this? The first part of the question got cutoff but it states, for any integer n greater than or equal to 1, prove that:


Extracted text: (e) 1 +33 +5 + +(2n – 1) = n²(2n² – 1). [Hint: Separate the left-hand side of the identity 1' +2' +3° + ...+ (2n) [(2n)(2n + 1)] 2 into odd and even terms and solve for the sum of odd cubes.]