During tough times like these, investment becomes more uncertain with more dangers. To solve it, we might try to train a model to decide when to buy or sell. Therefore, to provide it with correct...


During tough times like these, investment becomes more uncertain with more dangers. To solve it, we might try to train a model to decide when to buy or sell. Therefore, to provide it with correct data, we plan to design an algorithm that answers:



  • what is the perfect moment to buy and when to sell to maximize your profit?
    Assume you must buy



Input:


???????: array listing ??????? ?? ??? ??????, where indices represent days; it has at least two valueschanges: array listing changes in the prices, where indices represent days; it has at least two values


Output:


???????????:index of the change before which we buy:index of the change before which we sell:the profit of this intervali:index of the change before which we buyj:index of the change before which we sellmaxProfit:the profit of this interval


Example:
Assume the below table contains the prices of a particular stock over days



As we in general, try to solve the problem first; we start with a brute force, simple, algorithm: design it below<br>In [ ]: # write your implementation here<br>def maxProfitBrute(changes):<br>it returns the indices of (i,j) indicating the day to buy and sell respectively<br>to have the maximum profit in a list of prices per day in <changes>.<br>Inputs:<br>- changes: the list holding the changes in prices; the value whose index is k represents<br>the change between day <k> and day <k+1><br><changes> has at least a single change [two days]<br>Output:<br>i: the index of the change before which we buy<br>- j: the index of the change after which we sell<br>- maxProfit: the value of the maximum profit<br>Example:<br>changes = [1,2]<br>that means the price started with <x>;<br>- day 1: it became <x+1><br>- day 2: it became <x+3><br>In that case: (i,j) = (0,1) as we should buy at the first day, and sell after the third day<br>II II I<br># return the values<br>return (0,0,0)<br>In [ ]: # Try your algorithm<br>maxProfitBrute([13,7,-30,15,10,-5,12,7,-11,6])<br>Divide and Conquer<br>Now, we would try to use a divide and conquer paradigm. Hint: try the three steps, and design multiple versions to master these steps<br>

Extracted text: As we in general, try to solve the problem first; we start with a brute force, simple, algorithm: design it below In [ ]: # write your implementation here def maxProfitBrute(changes): it returns the indices of (i,j) indicating the day to buy and sell respectively to have the maximum profit in a list of prices per day in . Inputs: - changes: the list holding the changes in prices; the value whose index is k represents the change between day and day has at least a single change [two days] Output: i: the index of the change before which we buy - j: the index of the change after which we sell - maxProfit: the value of the maximum profit Example: changes = [1,2] that means the price started with ; - day 1: it became - day 2: it became In that case: (i,j) = (0,1) as we should buy at the first day, and sell after the third day II II I # return the values return (0,0,0) In [ ]: # Try your algorithm maxProfitBrute([13,7,-30,15,10,-5,12,7,-11,6]) Divide and Conquer Now, we would try to use a divide and conquer paradigm. Hint: try the three steps, and design multiple versions to master these steps
Input:<br>changes : array listing changes in the prices, where indices represent days; it has at least two values<br>Output:<br>i : index of the change before which we buy<br>j: index of the change before which we sell<br>maxProfit : the profit of this interval<br>Example:<br>Assume the below table contains the prices of a particular stock over days<br>prices<br>changes<br>Day Value<br>50<br>63<br>13<br>2<br>70<br>7<br>40<br>-30<br>4<br>55<br>15<br>65<br>10<br>6.<br>60<br>-5<br>7<br>72<br>12<br>8<br>79<br>7<br>68<br>-11<br>10<br>74<br>Therefore, the output of maxProfit([13,7,-30,15,10,-5,12,7,-11,6]) should be (3, 7, 39) .This is because our maximum profit would be 39<br>when we buy the stock at day 4, index of 3, and sell after day 8, index of 7. Then, the total profit is 15 + 10 – 5 + 12 +7 = 39<br>We will try to solve the problem using various techniques:<br>• Brute-Force<br>• Divide-and-Conquer<br>

Extracted text: Input: changes : array listing changes in the prices, where indices represent days; it has at least two values Output: i : index of the change before which we buy j: index of the change before which we sell maxProfit : the profit of this interval Example: Assume the below table contains the prices of a particular stock over days prices changes Day Value 50 63 13 2 70 7 40 -30 4 55 15 65 10 6. 60 -5 7 72 12 8 79 7 68 -11 10 74 Therefore, the output of maxProfit([13,7,-30,15,10,-5,12,7,-11,6]) should be (3, 7, 39) .This is because our maximum profit would be 39 when we buy the stock at day 4, index of 3, and sell after day 8, index of 7. Then, the total profit is 15 + 10 – 5 + 12 +7 = 39 We will try to solve the problem using various techniques: • Brute-Force • Divide-and-Conquer

Jun 06, 2022
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