During a reversible process, 396 kJ of heat is added to 1.264 kg of a certain gas while the volume is held constant. For this gas, Cp =2.112 kJ/(kg-K) and Cv = 1.625 kJ/(kg-K). The initial temperature...


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During a reversible process, 396 kJ of heat is added to 1.264 kg of a certain gas while the<br>volume is held constant. For this gas, Cp =2.112 kJ/(kg-K) and Cv = 1.625 kJ/(kg-K). The<br>initial temperature is 26.7°C and the initial pressure is 586 kPa. Determine the following:<br>(1) The universal gas rate constant for the gas is<br>we relate the two heat capacity values?)<br>kJ/(kg-K) (Hint: How do<br>m3<br>(Hint: If the ideal gas equation is expressed in<br>(2) The volume, V =<br>terms of mass, it becomes PV=mRT)<br>(3) The final pressure, P2 =<br>kPa<br>(4) The final temperature, T2 =<br>°C<br>(5) W =<br>kJ<br>(6) Q =<br>kJ<br>(7) DU =<br>kJ<br>%3D<br>(8) DH =<br>kJ<br>

Extracted text: During a reversible process, 396 kJ of heat is added to 1.264 kg of a certain gas while the volume is held constant. For this gas, Cp =2.112 kJ/(kg-K) and Cv = 1.625 kJ/(kg-K). The initial temperature is 26.7°C and the initial pressure is 586 kPa. Determine the following: (1) The universal gas rate constant for the gas is we relate the two heat capacity values?) kJ/(kg-K) (Hint: How do m3 (Hint: If the ideal gas equation is expressed in (2) The volume, V = terms of mass, it becomes PV=mRT) (3) The final pressure, P2 = kPa (4) The final temperature, T2 = °C (5) W = kJ (6) Q = kJ (7) DU = kJ %3D (8) DH = kJ

Jun 09, 2022
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