DO NOT ANSWER IF YOU ARE NOT WILLING TO ANSWER PROPERLY. LEAVE IT FOR SOMEONE MORE DEDICATED AND SOMEONE WHO CAN ANSWER CORRECTLY. THIS IS THE THIRD TIME I AM POSTING THE SAME QUESTION IF I DO NOT GET...



DO NOT ANSWER IF YOU ARE NOT WILLING TO ANSWER PROPERLY. LEAVE IT FOR SOMEONE MORE DEDICATED AND SOMEONE WHO CAN ANSWER CORRECTLY. THIS IS THE THIRD TIME I AM POSTING THE SAME QUESTION IF I DO NOT GET PROPER ANSWER WITH A GOOD EXPLANATION THAT WILL CLEAR MY CONCEPTS THIS TIME, I AM LEAVING BARTLEBY. IT'S FRUSTRATING!!!




Please help me with these questions urgently. Please answer all questions with neat workings to get a 'like'. The questions require you to calculate the run time of the code snippets in terms of Big-oh. Please provide detailed workings of the final answer.



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Please help me with these questions urgently. Please answer all questions with neat workings to get a 'like'. The questions require you to calculate the run time of the code snippets in terms of Big-oh. Please provide detailed workings of the final answer.




From the following code snippets find out the time complexity (Big-Oh)<br>i=1<br>k=1<br>k=1<br>while(k>n):<br>while (k<n):<br>k=k+100<br>k=k+i<br>i++<br>sum = 100<br>sum = 100<br>k=1<br>k=1<br>while(k<n):<br>while (k<n):<br>sum = k * k +sum<br>for(j = 2; j <n ; j = j + 2)<br>print(sum)<br>k = k * 3<br>sum = k * k +sum<br>k = k * 3<br>

Extracted text: From the following code snippets find out the time complexity (Big-Oh) i=1 k=1 k=1 while(k>n): while (k
sum = 100<br>k=1<br>sum = 100<br>while (k<n):<br>k=1<br>for(j = 2; j <n; j = j * 2)<br>for (i=1;1 <j ; i++)<br>if(i*j==1)<br>%3D<br>while (k<n):<br>for(j = 2; j <n ; j = j * 2)<br>for (i=1;1 <j ; i++)<br>break<br>k++<br>k++<br>

Extracted text: sum = 100 k=1 sum = 100 while (k

Jun 09, 2022
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