Determine the upper-tail critical value t in each of the following circumstances. a. 1-a= 0.95, n = 52 d. 1-a=0.95, n= 42 e. 1-a=0.99 n = 10 b. 1-a=0.90,n=52 c. 1-a=0.95, n= 32 a. t= (Round to four...

Plz solve correctly i need correcrt exact answer i am posting this third time plz give mn correct answersDetermine the upper-tail critical value t in each of the following circumstances.<br>a. 1-a= 0.95, n = 52<br>d. 1-a=0.95, n= 42<br>e. 1-a=0.99 n = 10<br>b. 1-a=0.90,n=52<br>c. 1-a=0.95, n= 32<br>a. t=<br>(Round to four decimal places as needed.)<br>b. t (Round to four decimal places as needed.)<br>c.t= (Round to four decimal places as needed.)<br>d. t= (Round to four decimal places as needed.)<br>e.t= (Round to four decimal places as needed.)<br>

Extracted text: Determine the upper-tail critical value t in each of the following circumstances. a. 1-a= 0.95, n = 52 d. 1-a=0.95, n= 42 e. 1-a=0.99 n = 10 b. 1-a=0.90,n=52 c. 1-a=0.95, n= 32 a. t= (Round to four decimal places as needed.) b. t (Round to four decimal places as needed.) c.t= (Round to four decimal places as needed.) d. t= (Round to four decimal places as needed.) e.t= (Round to four decimal places as needed.)
E Confiden<br>Population Mean<br>me<br>Determine the upper-tail critical value t,2 in each of the following circumstances.<br>rk<br>a. 1-a = 0.95, n = 52<br>d. 1-a= 0.95, n = 42<br>b. 1-a=0.90, n = 52<br>e. 1-a=0.99,n= 10<br>a Tests<br>c. 1-a= 0.95, n = 32<br>book<br>O One or more of your responses is incorrect.<br>Crunch<br>a. t=2.0076| (Round to four decimal places as needed.<br>For the level of confidence (1- a) x 100%, a is the proportion in the tails of the<br>distribution that is outside the confidence interval. That is, the proportion in the<br>upper tail of the distribution is a/2 and the proportion in the lower tail of the<br>distribution is a/2. Locate the critical value on a table of critical values of t using<br>a/2 and df = n-1.<br>xt<br>b. t= 1,6753 (Round to four decimal places as needed.)<br>c. t=2.0395 (Round to four decimal places as needed.<br>d. t= 2.02 (Round to four decimal places as needed.)<br>Incorrect: 0<br>e.t=3.25 (Round to four decimal places as needed.)<br>OK<br>Clear all<br>Check answer<br>Ask my instructor<br>Question 36 (0/1)<br>Question 35 (0/1)<br>Question 34 (0/1)<br>/ Question 33 (1/1)<br>Question 37 (0/1)<br>ENG<br>-2°C Mostly cdoudy<br>

Extracted text: E Confiden Population Mean me Determine the upper-tail critical value t,2 in each of the following circumstances. rk a. 1-a = 0.95, n = 52 d. 1-a= 0.95, n = 42 b. 1-a=0.90, n = 52 e. 1-a=0.99,n= 10 a Tests c. 1-a= 0.95, n = 32 book O One or more of your responses is incorrect. Crunch a. t=2.0076| (Round to four decimal places as needed. For the level of confidence (1- a) x 100%, a is the proportion in the tails of the distribution that is outside the confidence interval. That is, the proportion in the upper tail of the distribution is a/2 and the proportion in the lower tail of the distribution is a/2. Locate the critical value on a table of critical values of t using a/2 and df = n-1. xt b. t= 1,6753 (Round to four decimal places as needed.) c. t=2.0395 (Round to four decimal places as needed. d. t= 2.02 (Round to four decimal places as needed.) Incorrect: 0 e.t=3.25 (Round to four decimal places as needed.) OK Clear all Check answer Ask my instructor Question 36 (0/1) Question 35 (0/1) Question 34 (0/1) / Question 33 (1/1) Question 37 (0/1) ENG -2°C Mostly cdoudy
Jun 11, 2022
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