Determine the equations of the elastic curve for the shaft using the x1 and x2 coordinates. Take El as constant and Mo = 900 N.m. %3D M, A В X2 1 m 4 m Select one: V1 (x) =(1/EI). (-37.5 x,3 - 600 x1)...

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Determine the equations of the elastic curve for the shaft using the x1 and x2 coordinates.<br>Take El as constant and Mo = 900 N.m.<br>%3D<br>M,<br>A<br>В<br>X2<br>1 m<br>4 m<br>Select one:<br>V1 (x) =(1/EI). (-37.5 x,3 - 600 x1) {m} and V2 (x) = (1/EI). (450 x22 – 2100 x2 - 1650) {m}<br>V1 (x) =(1/EI). (37.5 x13 - 600 x1) {m} and V2 (x) = (1/EI). (450 x2² + 2100 x2 + 1650) {m}<br>25°C Mostly sunny<br>

Extracted text: Determine the equations of the elastic curve for the shaft using the x1 and x2 coordinates. Take El as constant and Mo = 900 N.m. %3D M, A В X2 1 m 4 m Select one: V1 (x) =(1/EI). (-37.5 x,3 - 600 x1) {m} and V2 (x) = (1/EI). (450 x22 – 2100 x2 - 1650) {m} V1 (x) =(1/EI). (37.5 x13 - 600 x1) {m} and V2 (x) = (1/EI). (450 x2² + 2100 x2 + 1650) {m} 25°C Mostly sunny
Select one:<br>V1 (x) =(1/ElI). (-37.5 x, – 600 x) {m} and V2 (x) = (1/EI). (450 x22 – 2100 x2 - 1650) {m}<br>V1 (x) =(1/EI). (37.5 x, – 600 x1) {m} and V2 (x) = (1/EI). (450 x2“ + 2100 x2 + 1650) {m}<br>V1 (x) =(1/EI). (37.5 x13 - 600 x1) {m} and V2 (X) = (1/EI). (-450 x22 + 2100 x2 + 1650) {m}<br>O v1 (x) =(1/EI). (37.5 x,3 + 600 x,) {m} and V2 (x) = (1/EI). (450 x22 – 2100 x2 + 1650) {m}<br>V1 (X) =(1/EI). (37.5 x13 – 600 x1) {m} and V2 (X) = (1/EI). (450 x22 - 2100 x2 + 1650) {m}<br>

Extracted text: Select one: V1 (x) =(1/ElI). (-37.5 x, – 600 x) {m} and V2 (x) = (1/EI). (450 x22 – 2100 x2 - 1650) {m} V1 (x) =(1/EI). (37.5 x, – 600 x1) {m} and V2 (x) = (1/EI). (450 x2“ + 2100 x2 + 1650) {m} V1 (x) =(1/EI). (37.5 x13 - 600 x1) {m} and V2 (X) = (1/EI). (-450 x22 + 2100 x2 + 1650) {m} O v1 (x) =(1/EI). (37.5 x,3 + 600 x,) {m} and V2 (x) = (1/EI). (450 x22 – 2100 x2 + 1650) {m} V1 (X) =(1/EI). (37.5 x13 – 600 x1) {m} and V2 (X) = (1/EI). (450 x22 - 2100 x2 + 1650) {m}

Jun 11, 2022
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