Determine the centroidal moment of inertia. **correction in picture L200x200x20 L 200 x 200 x 20 theoretical mass: 59.7 kg/m area: 7600 mm 2 I: 28.8 x 10 6 mm 4 S (I/C) :202 x 10 3 mm 3 r: 61.6 mm x...






Determine the centroidal moment of inertia.


**correction in picture L200x200x20



L 200 x 200 x 20

theoretical mass: 59.7 kg/m
area: 7600 mm2

I: 28.8 x 106
mm4

S (I/C) :202 x 103
mm3

r: 61.6 mm
x or y: 57.4 mm
Axis z r: 39.3 mm





C380 x 74


theoretical mass: 74.4 kg/m
area:  9480 mm2

depth: 381 mm

flange width: 94 mm
flange thickness: 16.5 mm

web thickness: 18.2 mm

axis x I: 168 x 106
mm4

axis x S (I/C) :881 x103
mm3

axis x r: 133 mm

axis y I: 4.60 x 106
mm4

axis y S (I/C) :62.4 x103
mm3

axis y r: 22.0 mm
x: 20.3 mm






W310 x 500


theoretical mass: 500.4 kg/m
area:  63700 mm2

depth: 427 mm

flange width: 340 mm
flange thickness: 75.1 mm

web thickness: 45.1 mm

axis x I: 1690 x 106
mm4

axis x S (I/C) :7910  x 103
mm3

axis x r: 163 mm

axis y I: 494 x 106
mm4

axis y S (I/C) :2910 x103
mm3

axis y r: 88.1 mm























































L 200 X 200<br>C380x74<br>W 310 x 500<br>1C980x74<br>E180 170<br>

Extracted text: L 200 X 200 C380x74 W 310 x 500 1C980x74 E180 170

Jun 10, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers