Design and perform a cross between a female fly with vestigial wing size and a male fly with an incomplete wing vein mutation. Carefully study the phenotype of this male fly to be sure that you...

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Design and perform a cross between a female fly with vestigial wing size and a male fly with an incomplete wing vein mutation. Carefully study the phenotype of this male fly to be sure that you understand the effect of the incomplete allele.What did you observe in the F1
generation?

Note: It may be helpful to click up and down in this display box to closely compare the phenotypes of the F1
and P generations.

Was this what you expected? Why or why not? Once you have produced an F1
generation, mate F1
flies to generate an F2
generation.


Study the results of your F2
generation and then answer the following questions.

Which mutation is epistatic? Is the vestigial mutation dominant or recessive? Determine the phenotypic ratio that appeared in the dihybrid F2
generation, and use chi-square analysis to accept or reject this ratio.


  1. Perform another experiment by mating a female fly with the apterous wing size mutation with a male fly with the radius incomplete vein structure mutation. Follow this cross to the F2
    generation.


Which mutation is epistatic? Is the apterous wing mutation dominant or recessive?



Assignment #2:
Recombination



Mendel's law of independent assortment applies to unlinked alleles, but
linked genes--genes on the same chromosome -- do not assort independently. Yet linked genes are not always inherited together because of
crossing over. Crossing over, or
homologous recombination, occurs during prophase of meiosis I when segments of DNA are exchanged between homologous chromosomes. Homologous recombination can produce new and different combinations of alleles in offspring. Offspring with different combinations of phenotypes compared with their parents are called
recombinants. The frequency of appearance of recombinants in offspring is known as recombination frequency. Recombination frequency represents the frequency of a crossing--over event between the loci for linked alleles. If two alleles for two different traits are located at different positions on the same chromosome (heterozygous loci) and these alleles are far apart on the chromosome
Answered Same DayDec 22, 2021

Answer To: Design and perform a cross between a female fly with vestigial wing size and a male fly with an...

Robert answered on Dec 22 2021
124 Votes
1. Design and perform a cross between a female fly with vestigial wing size and a male fly with
an incomplete wing vein mutation. Carefully study the phenotype of this male fly to be sure
that you understand the effect of the incomplete allele.
Allele for vestigial wing Vg which is recessive for normal wing Vg+
Allele for incomplete vein is RI which is recessive for normal vein RI
Thus genotype
of female is VgVg RI+RI+
Genotype of male is Vg+Vg+RIRI
Cross can be represented as
VgVg RI+RI+ X Vg+Vg+RIRI
F1 progeny: Vg+VgRI+RI: All wild type
Cross between F1 offspring
Vg+VgRI+RI X Vg+VgRI+RI
Result can be represented in punnet square:
gametes female Vg+RI+ Vg RI+ Vg+RI VgRI
male
Vg+RI+ Vg+ Vg+RI+RI+
Wild type
Vg+ VgRI+RI+
Wild type
Vg+ Vg+RI+RI
Wild type
Vg+ VgRI+RI
Wild type
VgRI+ Vg+ VgRI+RI+
Wild type
Vg VgRI+RI+
Vestigial
Vg+ VgRI+RI
Wild type
Vg VgRI+RI
vestigial
Vg+RI Vg+ Vg+RI+RI
Wild type
Vg+ VgRI+RI
Wild type
Vg+ Vg+RIRI
Incomplete vein
Vg+ VgRIRI
Incomplete vein
VgRI Vg+ VgRI+RI
Wild type
VgVgRI+RI
vestigial
Vg+ VgRIRI
Incomplete vein
Vg VgRIRI
Incomplete vein
Phenotypic frequency: 9 wild type: 3 vestigial: 4 incomplete vein fly.
Thus in F1 generations all offsprings are wilds type. This is expected because according to
Mendelian theory dominant allele would express over the recessive. This is the case here.
In F2 generation result shows that phenotypic ratio of offspring is 9 wild type: 3 vestigial: 4
incomplete vein fly.
This result does not follow the Mendel’s rule, because for dihybrid cross phenotypic ration of F2
is 9:3:3:1
Here this phenotypic ration indicates the presence of recessive epistasis. Because offsprings with
homozygous allele for incomplete vein (RI) are recessive and their phenotype is incomplete vein.
Thus, incomplete vein gene (RI) is recessive epistatic over vestigial wing gene ( Vg). And
vestigial wing gene (Vg) is hypostatic gene.
2. Perform another experiment by mating a female fly with the apterous wing size mutation
with a male fly with the radius incomplete vein structure mutation. Follow this cross to
the F2 generation.
Which mutation is epistatic? Is the apterous wing mutation dominant or recessive?
Allele for apterous wing size mutation is Ap
Allele for radius incomplete vein structure mutation is RI
Genotype of female would be ApApRI+RI+
Genotype of male would be Ap+Ap+RIRI
Cross can be represented as
ApApRI+RI+ X AP+Ap+RIRI
F1: AP+ApRI+RI = all wild type.
F2: Ap+ApRI+RI X : Ap+ApRI+RI
This can be presented in punnet square:
gametes female Ap+RI+ ApRI+ AP+RI ApRI
male
Ap+RI+ Ap+ Ap+RI+RI+
Wild type
Ap+ ApRI+RI+
Wild type
Ap+ Ap+RI+RI
Wild type
Ap+ ApRI+RI
Wild type
ApRI+ Ap+ ApRI+RI+
Wild type
ApApRI+RI+
Apterous
Ap+ApRI+RI
Wild type
Ap ApRI+RI
Apterous
Ap+RI Ap+ Ap+RI+RI
Wild type
Ap+ ApRI+RI
Wild type
Ap+ Ap+RIRI
Incomplete vein
Ap+ ApRIRI
Incomplete vein
ApRI Ap+ ApRI+RI
Wild type
ApApRI+RI
Apterous
Ap+ ApRIRI
Incomplete vein
ApApRIRI
Incomplete vein
Phenotypic frequency: 9 wild type : 3 vestigial : 4 incomplete vein fly.
In F2 generation result shows that phenotypic ratio of offspring is 9 wild type : 3 apterous : 4
incomplete vein fly.
This result does not follow the Mendel’s rule, because for dihybrid cross phenotypic ration of F2
is 9:3:3:1
Here this phenotypic ration indicates the presence of recessive epistasis. Because offsprings with
homozygous allele for incomplete vein (RI) are recessive and their phenotype is incomplete vein.
Thus, incomplete vein gene (RI) is recessive epistatic over apterous wing gene( Vg).
Apterous wing is recessive wing.
Assignment #2:
1. To understand how recombination frequencies can be used to determine an approximate
map distance between closely linked genes, cross a female fly with the eyeless mutation
for eye shape with a male fly...
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