/ ** * Definition for a binary tree node. * / public class TreeNode { int val; Practice 1 Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the...


Please answer the question in the screenshot. The language used here is Java. Please use the starting code.



/ **<br>* Definition for a binary tree node.<br>* /<br>public class TreeNode {<br>int val;<br>Practice 1<br>Given a binary tree and a sum,<br>determine if the tree has a root-to-leaf<br>path such that adding up all the values<br>along the path equals the given sum.<br>Note: A leaf is a node with no children.<br>TreeNode left;<br>TreeNode right;<br>TreeNode (int x) { val = x; }<br>}<br>Example: Given the below binary tree<br>and sum = 22,<br>class TreeDFS {<br>%3D<br>5<br>public boolean hasPathSum(TreeNode root, int sum) {<br>}<br>}<br>4 8<br>11 13 4<br>7 2<br>1<br>return true, as there exist a<br>root-to-leaf path 5->4->11->2 which<br>sum is 22.<br>

Extracted text: / ** * Definition for a binary tree node. * / public class TreeNode { int val; Practice 1 Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum. Note: A leaf is a node with no children. TreeNode left; TreeNode right; TreeNode (int x) { val = x; } } Example: Given the below binary tree and sum = 22, class TreeDFS { %3D 5 public boolean hasPathSum(TreeNode root, int sum) { } } 4 8 11 13 4 7 2 1 return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

Jun 07, 2022
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