def function(n): while n>0: n=(n/2) can n be ever equal to 0? What is the time complexity of this function? What if it's n=(n/2) + 1


def function(n):<br>while n>0:<br>n=(n/2)<br>can n be ever equal to 0? What is the time complexity of this function? What if it's n=(n/2) + 1<br>

Extracted text: def function(n): while n>0: n=(n/2) can n be ever equal to 0? What is the time complexity of this function? What if it's n=(n/2) + 1

Jun 09, 2022
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