Create your problem: It is reported that the average hours of sleep of all teenagers is 6.5 hours. Here is a sample of the hours of sleep of 20 random teenagers: 7.5 6 6.5 8 9 | 106.5 8| 8 67.5 9 7...


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Create your problem:<br>It is reported that the average hours of sleep of all teenagers is 6.5 hours. Here is<br>a sample of the hours of sleep of 20 random teenagers:<br>7.5 6 6.5 8<br>9 |<br>106.5 8| 8<br>67.5 9<br>7 6.5 || | 5<br>Is there enough evidence at the 5% level that<br>the average hours of sleep of a teenager is<br>greater than 6.5 hours?<br>6|6<br>17<br>Step #1: hypothesize<br>List what is given:<br>5<br>l = 6.5<br>X = 7,28<br>N= 20<br>%3D<br>X=0.05<br>List your Ho and Ha: Ho: l = 6.5 The average hours of sleep of a teenager is<br>equal to 6.5 hours.<br>Haill76.5 The average hours of sleep of a teenager is<br>greater than 6.5 hours.<br>Step #2: Prepare Check conditions:<br>Condition #1: Random sample and independent → Random is stated.<br>Condition #2: Normal- Assume is normal.<br>Condition #3: Big population must be at least 10 times larger than the sample size.<br>Population>10(Sample Size)→ All teenagers > 10(20) = 200<br>Extra by hand: lM =6.5 X=7.28 S-1.585 n= 20<br>SE =S = 1.585 =0.3544<br>20<br>+-X-U = Z.28-6.5=2.20<br>0.3544<br>The critical value from the t table is (df =19 at 95%): 2.09<br>Since our t = 2.20 the p-value would be smaller than p-value for † - 2.09<br>%3D<br>

Extracted text: Create your problem: It is reported that the average hours of sleep of all teenagers is 6.5 hours. Here is a sample of the hours of sleep of 20 random teenagers: 7.5 6 6.5 8 9 | 106.5 8| 8 67.5 9 7 6.5 || | 5 Is there enough evidence at the 5% level that the average hours of sleep of a teenager is greater than 6.5 hours? 6|6 17 Step #1: hypothesize List what is given: 5 l = 6.5 X = 7,28 N= 20 %3D X=0.05 List your Ho and Ha: Ho: l = 6.5 The average hours of sleep of a teenager is equal to 6.5 hours. Haill76.5 The average hours of sleep of a teenager is greater than 6.5 hours. Step #2: Prepare Check conditions: Condition #1: Random sample and independent → Random is stated. Condition #2: Normal- Assume is normal. Condition #3: Big population must be at least 10 times larger than the sample size. Population>10(Sample Size)→ All teenagers > 10(20) = 200 Extra by hand: lM =6.5 X=7.28 S-1.585 n= 20 SE =S = 1.585 =0.3544 20 +-X-U = Z.28-6.5=2.20 0.3544 The critical value from the t table is (df =19 at 95%): 2.09 Since our t = 2.20 the p-value would be smaller than p-value for † - 2.09 %3D
Create your problem:<br>Compare your p-value to the significance level:<br>p-value =O compared alpha 0.05. The p-valuc is smaller than alpha.<br>Step #4: Interpret Write your conclusion:<br>We reject Ho . There is statistically significant evidence to rejoct +Hto<br>(p=0). We conclude the average hours of skep of teenagers is grcatar<br>than 6.5 hours.<br>Confidence interval:<br>Condition #1: Random sample and independent<br>Random is stated.<br>Condition #2: Normal Assume is normal.<br>Find the following:<br>X= 7. 28<br>S=1.585<br>N= 20<br>+*= 2.09<br>又++()<br>7.28± 2.09(0.35H4)<br>7.28-0.7407<br>7.28 +0:7407<br>6.5393<br>8.0207<br>95% Confident Interval: We are 95% confident the average hours of sleep<br>of teenagers is between 6.54 to 8.02 hours.<br>

Extracted text: Create your problem: Compare your p-value to the significance level: p-value =O compared alpha 0.05. The p-valuc is smaller than alpha. Step #4: Interpret Write your conclusion: We reject Ho . There is statistically significant evidence to rejoct +Hto (p=0). We conclude the average hours of skep of teenagers is grcatar than 6.5 hours. Confidence interval: Condition #1: Random sample and independent Random is stated. Condition #2: Normal Assume is normal. Find the following: X= 7. 28 S=1.585 N= 20 +*= 2.09 又++() 7.28± 2.09(0.35H4) 7.28-0.7407 7.28 +0:7407 6.5393 8.0207 95% Confident Interval: We are 95% confident the average hours of sleep of teenagers is between 6.54 to 8.02 hours.
Jun 08, 2022
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