cos x XXXXXXXXXXsin x ------- + ----------- 1+ sin x cos x

# 1 [cosx/ (1+sinx)] + [(1+sinx)/cosx)]
Solution:
Rationalize denominator which contains Denominator (1+sinx)
= {(cosx)/(1+sinx)} * {(1-sinx)/(1-sinx)} + ((1+sinx)/cosx)
= [(1-sinx)*cosx]/ [(1-sinx) (1+sinx)] + ((1+sinx)/cosx)
= [cosx (1-sinx)]/cos2x + ((1+sinx)/cosx) ...