The problems that are listed below need to be solved and you may access those problems via viewing the attached images. The problems are 2.26; 2.27; 2.28; 2.29.
Extracted text: correct number of significant figures. 2.26. WP The Prandtl number, Npr, is a dimensionless group important in heat-transfer calculations. It is defined as C,e/k, where C, is the heat capacity of a fluid, µ is the fluid viscosity, and k is the thermal conductivity. For a particular fluid, C, = 0.583 J/(g : °C), k = 0.286 W/(m °C), and u (remember, it is dimensionless), showing your calculations; then determine it with a calculator. 1936 lbm/(ft · h). Estimate the value of Np, without using a calculator Answer 2.27. The Reynolds number is a dimensionless group defined for a fluid flowing in a pipe as Re Dup/μ where D is pipe diameter, u is fluid velocity, p is fluid density, and u is fluid viscosity. When the value of the Reynolds number is less than about 2100, the flow is laminar-that is, the fluid flows in smooth streamlines. For Reynolds numbers above 2100, the flow is turbulent, characterized by a great deal of agitation. Liquid methyl ethyl ketone (MEK) flows through a pipe with an inner diameter of 2.067 inches at an average velocity of o.48 ft/s. At the fluid temperature of 20°C the density of liquid MEK is o.805 g/cm3 and the viscosity is o.43 centipoise [ 1 cP = 1.00 x 10¬³ kg/(m · s)]. Without using a calculator, determine whether the flow is laminar or turbulent. Show your -3 calculations.
Extracted text: 2.28. WP The following empirical equation correlates the values of variables in a system in which solid particles are suspended in a flowing gas: k,d,y 1/3 d,ир 1/2 2.00 + 0.600 D Both (u/pD) and (d,up/µ) are dimensionless groups; k, is a coefficient that expresses the rate at which a particular species transfers from the gas to the solid particles; and the coefficients 2.00 and o.600 are dimensionless constants obtained by fitting experimental data covering a wide range of values of the equation variables. The value of k, is needed to design a catalytic reactor. Since this coefficient is difficult to determine directly, values of the other variables are measured or estimated and k, is calculated from the given correlation. The variable values are as follows: d, 5.00 mm 0.100 (dimensionless) D 0.100 cm² /s 1.00 × 10-5 N ·s/m2 -3 3 1.00 x 10¬° g/cm' 10.0 m/s и a. What is the estimated value of k,? (Give its value and units.) Answer b. Why might the true value of k, in the reactor be significantly different from the value estimated in Part (a)? (Give several possible reasons.) c. Create a spreadsheet in which up to five sets of values of the given variables (d, through u) are entered in columns and the corresponding values of k, are calculated. Test your program using the following variable sets: (i) the values given above; (ii) as above, only double the particle diameter d, (making it 10.00 mm); (iii) as above, only double the diffusivity D; (iv) as above, only double the viscosity u; (v) as above, only double the velocity u. Report all five calculated values of k. 2.29. WP A seed crystal of diameter D (mm) is placed in a solution of dissolved salt, and new crystals are observed to nucleate (form) at a constant rate r (crystals/min). Experiments with seed crystals of different sizes show that the rate of nucleation varies with the seed crystal diameter as r(crystals/min) 200D – 10D² (Din mm) a. What are the units of the constants 200 and 10? (Assume the given equation is valid and therefore dimensionally homogeneous.) b. Calculate the crystal nucleation rate in crystals/s corresponding to a crystal diameter of o.050 inch. c. Derive a formula for r(crystals/s) in terms of D(inches). (See Example 2.6-1.) Check the formula using the result of Part (b).