Consider the weekly access time at Health Care II The Superintendent wants to investigate the average weekly access time (in hours) at Health Care II based on 2 different research questions. A random...


Consider the weekly access time at Health Care II<br>The Superintendent wants to investigate the average weekly access time (in hours) at Health Care II based on 2 different research questions. A random<br>sample of the weekly access times of n = 20 medical practitioners revealed an average of = 19.57 hours.<br>Let: u = mean weekly access time of the medical practitioners.<br>Research Question 1: Is the mean weekly access time less than 22 hours?<br>Given: The value of the test statistic is<br>z = -2.17<br>Complete the following:<br>Identify the correct null hypothesis:<br>О Но : и — 22<br>O Ho : a > 22<br>O Ho : a < 19.57<br>Но : а — 22<br>O Ho : ã + 19.57<br>О Но : и > 22<br>O Ho : µ + 19.57<br>O Ho : a = 19.57<br>O Ho : µ < 19.57<br>O Ho : a < 22<br>Ο H : μ+ 22<br>О Но : и < 22<br>O Ho : u<br>19.57<br>O Ho : a + 22<br>O Ho : a > 19.57<br>О Но : и>19.57<br>The p-value is:<br>Round your answer to 4 decimal places.<br>Research Question 2: Does the mean weekly access time differ from 21 hours?<br>

Extracted text: Consider the weekly access time at Health Care II The Superintendent wants to investigate the average weekly access time (in hours) at Health Care II based on 2 different research questions. A random sample of the weekly access times of n = 20 medical practitioners revealed an average of = 19.57 hours. Let: u = mean weekly access time of the medical practitioners. Research Question 1: Is the mean weekly access time less than 22 hours? Given: The value of the test statistic is z = -2.17 Complete the following: Identify the correct null hypothesis: О Но : и — 22 O Ho : a > 22 O Ho : a < 19.57="" но="" :="" а="" —="" 22="" o="" ho="" :="" ã="" +="" 19.57="" о="" но="" :="" и=""> 22 O Ho : µ + 19.57 O Ho : a = 19.57 O Ho : µ < 19.57="" o="" ho="" :="" a="">< 22="" ο="" h="" :="" μ+="" 22="" о="" но="" :="" и="">< 22="" o="" ho="" :="" u="" 19.57="" o="" ho="" :="" a="" +="" 22="" o="" ho="" :="" a=""> 19.57 О Но : и>19.57 The p-value is: Round your answer to 4 decimal places. Research Question 2: Does the mean weekly access time differ from 21 hours?
Research Question 2: Does the mean weekly access time differ from 21 hours?<br>Given: The 99% confidence interval for u is:<br>(16.7 , 22.4)<br>Complete the following:<br>and there is sufficient evidence to claim that the average<br>According to the observed confidence interval, the null hypothesis is<br>from 21 hours, at 0.01 level of significance.<br>access time<br>According to the observed confidence interval, we know that:<br>True<br>False<br>99% of all medical practitioners at Health Care Il have access times between 16.7 and 22.4<br>hours.<br>For every 100 random samples drawn, we expect that 99 of the confidence intervals will<br>contain the population mean.<br>We are 99% confident that u is between 16.7 and 22.4.<br>99% of all samples should have sample means between 16.7 and 22.4.<br>The probability that u is between 16.7 and 22.4 is 0.99.<br>For every 100 random samples drawn, we expect that 99 of the confidence intervals will<br>contain the sample mean.<br>O O O<br>O O O<br>

Extracted text: Research Question 2: Does the mean weekly access time differ from 21 hours? Given: The 99% confidence interval for u is: (16.7 , 22.4) Complete the following: and there is sufficient evidence to claim that the average According to the observed confidence interval, the null hypothesis is from 21 hours, at 0.01 level of significance. access time According to the observed confidence interval, we know that: True False 99% of all medical practitioners at Health Care Il have access times between 16.7 and 22.4 hours. For every 100 random samples drawn, we expect that 99 of the confidence intervals will contain the population mean. We are 99% confident that u is between 16.7 and 22.4. 99% of all samples should have sample means between 16.7 and 22.4. The probability that u is between 16.7 and 22.4 is 0.99. For every 100 random samples drawn, we expect that 99 of the confidence intervals will contain the sample mean. O O O O O O
Jun 10, 2022
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