Consider the system shown in below fig. phase 'b'is open due to conductor break.Calculate the sequence or symmetrical components of currents and also the neutral current. 50L0 A - 50120° A 50120 la0 =...

Consider the system shown in below fig. phase 'b'is open due to conductor<br>break.Calculate the sequence or symmetrical components of currents and also the<br>neutral current.<br>50L0 A<br>- 50120° A<br>50120<br>la0 = 16.66 L60, la1 = 33.33 LO, la2 = 16.66 L-60<br>%3D<br>000<br>

Extracted text: Consider the system shown in below fig. phase 'b'is open due to conductor break.Calculate the sequence or symmetrical components of currents and also the neutral current. 50L0 A - 50120° A 50120 la0 = 16.66 L60, la1 = 33.33 LO, la2 = 16.66 L-60 %3D 000

Jun 11, 2022

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Consider the system shown in below fig. phase 'b'is open due to conductor break.Calculate the sequence or symmetrical components of currents and also the neutral current. 50L0 A - 50120° A 50120 la0 =...

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