Consider the system shown in below fig. phase 'b'is open due to conductor break.Calculate the sequence or symmetrical components of currents and also the neutral current. = 50[0° A I, = 50[120° A...

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Extracted text: Consider the system shown in below fig. phase 'b'is open due to conductor break.Calculate the sequence or symmetrical components of currents and also the neutral current. = 50[0° A I, = 50[120° A 50/6º 5oL120° la0 = 17.77 L60, la1 = 44.44 LO, la2 = 17.77 L-60 In = 60L60 None of the above la0 = 15.55 L60, la1 = 66.66 LO, la2 = 15.55 L-60 In = 30L60 la0 = 16.66 L60, la1 = 33.33 LO, la2 = 16.66 L-60 In = 50L60