Consider the relation schema R=VWXYZ, with the set of functional dependencies F = {VW->XY, V>X, W->Z, YZ->Z, Z→V} A. Give three independent reasons why the following table cannot possibly be a legal...

Consider the relation schema R=VWXYZ,<br>with the set of functional dependencies F = {VW->XY, V>X, W->Z, YZ->Z, Z→V}<br>A. Give three independent reasons why the following table cannot possibly be a legal instance<br>of R.<br>V<br>W<br>X<br>Y<br>v1<br>w1<br>х1<br>yl<br>z1<br>v2<br>w1<br>x2<br>y2<br>z1<br>v2<br>w2<br>x1<br>y2<br>z2<br>B. Show the functional dependencies that hold on each of R1=VWX and R2=WYZ. You do not<br>need to show trivial functional dependencies, or those implied by others in the same set, but<br>you must show all others.<br>C. Is the decomposition of R into R1=VWX and R2=WYZ lossless-join? Why or why not?<br>

Extracted text: Consider the relation schema R=VWXYZ, with the set of functional dependencies F = {VW->XY, V>X, W->Z, YZ->Z, Z→V} A. Give three independent reasons why the following table cannot possibly be a legal instance of R. V W X Y v1 w1 х1 yl z1 v2 w1 x2 y2 z1 v2 w2 x1 y2 z2 B. Show the functional dependencies that hold on each of R1=VWX and R2=WYZ. You do not need to show trivial functional dependencies, or those implied by others in the same set, but you must show all others. C. Is the decomposition of R into R1=VWX and R2=WYZ lossless-join? Why or why not?

Jun 04, 2022

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Consider the relation schema R=VWXYZ, with the set of functional dependencies F = {VW->XY, V>X, W->Z, YZ->Z, Z→V} A. Give three independent reasons why the following table cannot possibly be a legal...

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