Consider the regular subdivision of the interval [a, b] as a = x0


Consider the regular subdivision of the interval [a, b] as a = x0 < xl < x2 < x3 < x4 =<br>b, with the step size h =<br>f(b) = 1, f(x1) = 1.5, f(x2) = f(x3)<br>2, then the approximation of I = f f(x)dx using composite Simpson's rule with n= 4 is:<br>Xi+1 - Xi, and define the functionf on [a, b] such that f(a) =<br>= 2. Suppose that the length of the interval [a, b] is<br>%3D<br>O 5<br>5/3<br>5/2<br>O 10/3<br>

Extracted text: Consider the regular subdivision of the interval [a, b] as a = x0 < xl="">< x2="">< x3="">< x4="b," with="" the="" step="" size="" h="f(b)" =="" 1,="" f(x1)="1.5," f(x2)="f(x3)" 2,="" then="" the="" approximation="" of="" i="f" f(x)dx="" using="" composite="" simpson's="" rule="" with="" n="4" is:="" xi+1="" -="" xi,="" and="" define="" the="" functionf="" on="" [a,="" b]="" such="" that="" f(a)="=" 2.="" suppose="" that="" the="" length="" of="" the="" interval="" [a,="" b]="" is="" %3d="" o="" 5="" 5/3="" 5/2="" o="">

Jun 04, 2022
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