Consider the regular subdivision of the interval [a, b] as a = x0


Consider the regular subdivision of the interval [a, b] as a = x0 < x1 < x2 < x3 < x4 =<br>b, with the step size h = x;+1 – x;, and define the function f on [a, b] such that f(a) =<br>f(b) = 1,f(x1) = 1.5, f(x2) = f(x3) = 2. Suppose that the length of the interval [a, b] is<br>3, then the approximation of I = f (x)dx using composite Simpson's rule with n= 4 is:<br>5/2<br>10/3<br>5/3<br>

Extracted text: Consider the regular subdivision of the interval [a, b] as a = x0 < x1="">< x2="">< x3="">< x4="b," with="" the="" step="" size="" h="x;+1" –="" x;,="" and="" define="" the="" function="" f="" on="" [a,="" b]="" such="" that="" f(a)="f(b)" =="" 1,f(x1)="1.5," f(x2)="f(x3)" =="" 2.="" suppose="" that="" the="" length="" of="" the="" interval="" [a,="" b]="" is="" 3,="" then="" the="" approximation="" of="" i="f" (x)dx="" using="" composite="" simpson's="" rule="" with="" n="4" is:="" 5/2="" 10/3="">

Jun 04, 2022
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