Consider the recurrence T(n) = n²/3 . T(n²/3) +n with base case T(n) = 1 for n

Recursion Trees

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Extracted text: Consider the recurrence T(n) = n²/3 . T(n²/3) +n with base case T(n) = 1 for n < 2.="" find="" an="" asymptotic="" solution="" using="" the="" method="" of="" recursion="" trees,="" presenting="" your="" answer="" as="" follows:="" (a)="" how="" deep="" is="" the="" recursion="" tree="" for="" t(n)?="" (b)="" what="" is="" the="" size="" of="" the="" subproblems="" at="" level="" d?="" (considering="" the="" root="" node="" to="" be="" at="" depth="" d="0)" (c)="" how="" many="" nodes="" does="" the="" tree="" have="" at="" level="" d?="" (hint:="" you="" may="" find="" the="" geometric="" series="" formula="" helpful.)="" (d)="" what="" is="" the="" total="" “non-recursive="" work"="" (i.e.,="" the="" sum="" of="" the="" non-recursive="" terms)="" at="" level="" d?="" (e)="" what="" is="" the="" asymptotic="" growth="" rate="" of="" t(n)?="" give="" a="" precise="" answer="" using="" the="" o="">